An aqueous solution of a nonvolatile solute boils at $373.052 K .(K_{b}=0.52$ and $K_{f}=1.86 K kg m

Question

An aqueous solution of a nonvolatile solute boils at $373.052 K .(K_{b}=0.52$ and $K_{f}=1.86 K kg mol^{-1}$ ) The solution freezes at

Professor PC Thomas Classes · Answer

$\Delta T_{b}=K_{b} m \quad \Delta T_{f}=K_{f} m \frac{\Delta T_{b}}{\Delta T_{f}}=\frac{K_{b}}{K_{f}} \quad \frac{0.052}{\Delta T_{f}}=\frac{0.52}{1.86} \Delta T_{f}=0.186 K, T_{f}=273-0.186=272.814 K$