A short electric dipole has a dipole moment of $16 imes 10^{-9} \mathrm{C} \mathrm{m}$. The electr

Question

A short electric dipole has a dipole moment of $16 	imes 10^{-9} \mathrm{C} \mathrm{m}$. The electric potential due to the dipole at a point at a distance of 0.6 m from the centre of the dipole, situated on a line making an angle of $60^{\circ}$ with the dipole axis is $\left(\frac{1}{4 \pi \varepsilon_{0}}=9 	imes 10^{9} \mathrm{~N} \mathrm{~m}^{2} / \mathrm{C}^{2}ight)$

Professor PC Thomas Classes · Answer

Potential due to dipole, $V=\frac{\vec{p} \cdot \hat{r}}{4 \pi \varepsilon_{0} r^{2}}=\frac{k p \cos 	heta}{r^{2}}$
or $\quad V=\frac{\left(9 	imes 10^{9}ight)\left(16 	imes 10^{-9}ight) 	imes \cos 60^{\circ}}{(0.6)^{2}}=200 \mathrm{~V}$