A parallel plate air capacitor is charged to a potential difference of $V$ volts. After disconnectin

Question

A parallel plate air capacitor is charged to a potential difference of $V$ volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an insulating handle. As a result the potential difference between the plates

Professor PC Thomas Classes · Answer

Capacitance of a parallel plate capacitor
$$
C=\frac{\varepsilon_{0} A}{d}
$$

When battery is disconnected and the distance between the plates of the capacitor is increased then capacitance decreases and charge remains constant.
Since, Charge $=$ Capacitance $	imes$ Potential difference
$	herefore \quad$ Potential difference increases.