The capacitance of a parallel plate capacitor with air as medium is $6 \mu \mathrm{~F}$. With the in

Question

The capacitance of a parallel plate capacitor with air as medium is $6 \mu \mathrm{~F}$. With the introduction of a dielectric medium, the capacitance becomes $30 \mu \mathrm{~F}$. The permittivity of the medium is $\left(\varepsilon_{0}=8.85 	imes 10^{-12} \mathrm{C}^{2} \mathrm{~N}^{-1} \mathrm{~m}^{-2}ight)$

Professor PC Thomas Classes · Answer

Given : capacitance without dielectric, $C=6 \mu \mathrm{~F}$ and capacitance with dielectric, $C^{\prime}=30 \mu \mathrm{~F}$.
$	herefore \quad$ Dielectric constant, $K=\frac{C^{\prime}}{C}=\frac{30}{6}=5$.
Now, permittivity of the medium, $\varepsilon=K \varepsilon_{0}$
$=5 	imes 8.85 	imes 10^{-12}=0.44 	imes 10^{-10} \mathrm{C}^{2} \mathrm{~N}^{-1} \mathrm{~m}^{-2}$