Let $R=\{(3,3),(6,6),(9,9),(12,12),(6,12),(3,9)$, $(3,12),(3,6)\}$ be a relation on the set $A=\{3,6

Question

Let $R=\{(3,3),(6,6),(9,9),(12,12),(6,12),(3,9)$, $(3,12),(3,6)\}$ be a relation on the set $A=\{3,6,9,12\}$. The relation is

Professor PC Thomas Classes · Answer

(d) : For $(3,9) \in R,(9,3) 
otin R$\ $	herefore$ Relation is not symmetric which means our choice (a) and (b) are out of court. We need to prove reflexivity and transitivity.\ For reflexivity $a \in R,(a, a) \in R$ which is hold i.e. $R$ is reflexive. Again, for transitivity of $(a, b)$ $\in R,(b, c) \in R \Rightarrow(a, c) \in R$\ which is also true in $R=\{(3,3),(6,6),(9,9)$, $(12,12),(6,12),(3,9),(3,12),(3,6)\}$.\