If $A, B$ are symmetric matrices of the same order, then $A B-B A$ is\

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(b)\ $(A B-B (a)^{T}=(A (b)^{T}-(B (a)^{T}$\ $=B^{T} A^{T}-A^{T} B^{T}$\ $=\mathrm{BA}-\mathrm{AB}$\ $=-(AB-BA)$\ $	herefore$ AB-BA is skew symmetric\