The dimensions of pressure are the same as that of\

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Professor PC Thomas Classes · Answer

(b) : Pressure $=\frac{	ext { Force }}{	ext { Area }}$ Therefore, dimensions of pressure $=\frac{\mathrm{MLT}^{-2}}{\mathrm{~L}^{2}}=\mathrm{ML}^{-1} \mathrm{~T}^{-2}$ and dimensions of energy per unit volume $$ =\frac{	ext { Energy }}{	ext { Volume }}=\frac{\mathrm{ML}^{2} \mathrm{~T}^{-2}}{\mathrm{~L}^{3}}=\mathrm{ML}^{-1} \mathrm{~T}^{-2} $$