A long solenoid of 50 cm length having 100 turns carries a current of 2.5 A . The magnetic field at

Question

A long solenoid of 50 cm length having 100 turns carries a current of 2.5 A . The magnetic field at the centre of the solenoid is ( $\mu_{0}=4 \pi 	imes 10^{-7} \mathrm{~T} \mathrm{~m} \mathrm{~A}^{-1}$ )\

Professor PC Thomas Classes · Answer

(a): Here, $l=50 \mathrm{~cm}, N=100, i=2.5 \mathrm{~A}$ Magnetic field inside the solenoid, $B=\mu_{0} n i=\frac{\mu_{0} N I}{l}$\ $B=\frac{4 \pi 	imes 10^{-7} 	imes 100 	imes 2.5}{0.5}=6.28 	imes 10^{-4} \mathrm{~T}$\