The mean free path of electrons in a metal is $4 imes 10^{-8} \mathrm{~m}$. The electric field whi

Question

The mean free path of electrons in a metal is $4 	imes 10^{-8} \mathrm{~m}$. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units $\mathrm{V} / \mathrm{m}$\

Professor PC Thomas Classes · Answer

(c) : Energy $=2 \mathrm{eV}=e E \lambda$\ $	herefore \quad E=\frac{2}{\lambda}=\frac{2}{4 	imes 10^{-8}}=5 	imes 10^{7} \mathrm{~V} / \mathrm{m}$\