A $4 \mu \mathrm{~F}$ capacitor is charged to 400 V . If its plates are joined through a resistance

Question

A $4 \mu \mathrm{~F}$ capacitor is charged to 400 V . If its plates are joined through a resistance of $2 \mathrm{k} \Omega$, then heat produced in the resistance is\

Professor PC Thomas Classes · Answer

(d) : Capacitance $(C)=4 \mu \mathrm{~F}=4 	imes 10^{-6} \mathrm{~F}$; Voltage $(\mathrm{V})$ $=400$ volts and resistance $(R)=2 \mathrm{k} \Omega=2 	imes 10^{3} \Omega$\ Heat produced $=$ Electrical energy stored $=\frac{1}{2} C V^{2}$ $$ =\frac{1}{2} 	imes\left(4 	imes 10^{-6}ight) 	imes(400)^{2}=0.32 \mathrm{~J} . $$