The net resistance of the circuit between $A$ and $B$ is\

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Professor PC Thomas Classes · Answer

(b) : This is a balanced Wheatstone's bridge so no current flows through the $7 \Omega$ resistor.\ $	herefore \quad \frac{1}{R_{e q}}=\frac{1}{4+3}+\frac{1}{6+8}$ or $R_{e q}=\frac{14}{3} \Omega$\