In analogy to $\mathrm{O}_{2}^{+}\left[\mathrm{PtF}_{6}\right]^{-}$a compound $\mathrm{N}_{2}^{+}\le

Question

In analogy to $\mathrm{O}_{2}^{+}\left[\mathrm{PtF}_{6}ight]^{-}$a compound $\mathrm{N}_{2}^{+}\left[\mathrm{PtF}_{6}ight]^{-}$will not be formed because the ionization energy of\

Professor PC Thomas Classes · Answer

$\mathrm{N}_{2}^{+}\left[\mathrm{PtF}_{6}ight]^{-}$will not be formed because ionization energy of $\mathrm{N}_{2}$ is very high.\