Dilute and concentrated NaOH reacts with chlorine to form respectively\

Question

Professor PC Thomas Classes · Answer

\begin{array}{cc}
\underset{(	ext{dil})}{2 \mathrm{NaOH}} + \mathrm{Cl}_{2} & ightarrow \mathrm{NaCl} + \mathrm{NaOCl} + \mathrm{H}_{2}\mathrm{O} \
\underset{	ext{Conc}}{6 \mathrm{NaOH}} + 3 \mathrm{Cl}_{2} & ightarrow 5 \mathrm{NaCl} + \mathrm{NaClO}_{3} + 3 \mathrm{H}_{2}\mathrm{O} \
\end{array}