The true statement about $\mathrm{CaOCl}_{2}$ is :\

Question

Professor PC Thomas Classes · Answer

Bleaching powder dissolves in sulphuric acid to give chlorine which acts s a bleaching agent\ $\mathrm{CaOCl}_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} ightarrow \mathrm{CaSO}_{4}+\mathrm{H}_{2} \mathrm{O}+\mathrm{Cl}_{2}$\ $\mathrm{CaOCl}_{2}$ is $\mathrm{Ca}^{2+}\left(\mathrm{Cl}^{-}ight)\left(\mathrm{OCl}^{-}ight)$\ The oxidation number of chlorine in\ $\mathrm{Cl}^{-}$is -1 and in $\mathrm{OCl}^{-}$is +1