Nitrogen forms $\mathrm{N}_{2}$, but phosphorus does not form $\mathrm{P}_{2}$, however, it converts

Question

Nitrogen forms $\mathrm{N}_{2}$, but phosphorus does not form $\mathrm{P}_{2}$, however, it converts $\mathrm{P}_{4}$, reason is\

Professor PC Thomas Classes · Answer

(b) : For strong $\pi$-bonding, $p \pi-p \pi$ bonding should be strong. In case of P , due to larger size as compared to N -atom, $p \pi-p \pi$ bonding is not so strong.