When $\mathrm{Cl}_{2}$ gas reacts with hot and concentrated sodium hydroxide solution, the oxidation

Question

When $\mathrm{Cl}_{2}$ gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from\

Professor PC Thomas Classes · Answer

(b) : $\quad \stackrel{0}{\mathrm{3Cl}_{2}} + \underset{	ext { (hot and conc.) }}{6 \mathrm{NaOH}}  ightarrow 5 \mathrm{Na} \stackrel{-1}{\mathrm{Cl}}+\stackrel{+5}{\mathrm{NaClO}_{3}}+3 \mathrm{H}_{2} \mathrm{O}$ This is an example of disproportionation reaction and oxidation state of chlorine changes from 0 to -1 and +5 .\