A man is moving on his bike with $54 \mathrm{~km} / \mathrm{hr}$. He takes a U-turn in 10 seconds an

Question

A man is moving on his bike with $54 \mathrm{~km} / \mathrm{hr}$. He takes a U-turn in 10 seconds and continues to move with the same magnitude of velocity. The average acceleration during this time is\

Professor PC Thomas Classes · Answer

$\Delta \mathrm{V}=54-(-54)=108 \mathrm{~km} / \mathrm{hr}$\