A particle is fired with a velocity $u$ making an angle $ heta$ with the horizontal. The magnitude

Question

A particle is fired with a velocity $u$ making an angle $	heta$ with the horizontal. The magnitude of the change in velocity after $t$ seconds is\

Professor PC Thomas Classes · Answer

There is no change in velocity along the horizontal direction. The change in velocity happens only in ventural direction.\ $\mathrm{v}_{\mathrm{y}}($ intial $)=\mathrm{v}_{0} \sin 	heta$\ $\mathrm{v}_{\mathrm{y}}($ final $)=\mathrm{v}_{0} \sin 	heta-\mathrm{gt}$\ The change in velocity $\mathrm{v}_{\mathrm{y}}($ final $)-\mathrm{v}_{\mathrm{y}}($ initial $)$\ $=\mathrm{v}_{0} \sin 	heta-\mathrm{gt}-\mathrm{v}_{0} \sin 	heta$\ $=-g t$\