A particle is moving at a speed $40 \mathrm{~ms}^{-1}$ on a circular track of radius 400 m . This sp

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A particle is moving at a speed $40 \mathrm{~ms}^{-1}$ on a circular track of radius 400 m . This speed is increasing at the rate of $3 \mathrm{~ms}^{-2}$. The acceleration of the particle is\

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\ $$ \begin{aligned} a_{r} & =\frac{v^{2}}{R}=\frac{40 	imes 40}{400}=4 \mathrm{~m} / \mathrm{s}^{2} \ a_{t} & =3 \mathrm{~m} / \mathrm{s}^{2} 	ext { (given) } \ a & =\sqrt{a_{r}^{2}+a_{t}^{2}} \ & = \end{aligned} $$