A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction $\frac{1}{\pi

Question

A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction $\frac{1}{\pi}\left(\frac{\mathrm{~Wb}}{\mathrm{~m}^{2}}ight)$ in such a way that its axis makes an angle of $60^{\circ}$ with $\vec{B}$. The magnetic flux linked with the disc is\

Professor PC Thomas Classes · Answer

(c) : $B=\frac{1}{\pi}\left(\frac{\mathrm{~Wb}}{\mathrm{~m}^{2}}ight)$ Area of the disc normal to $B$ is $\pi R^{2} \cos 60^{\circ}$.\ Flux $=B 	imes$ Area normal\ $	herefore$ Flux $=\frac{1}{2} 	imes 0.04=0.02 \mathrm{~Wb}$\