In a region of magnetic induction $B=10^{-2}$ tesla, a circular coil of radius 30 cm and resistance

Question

In a region of magnetic induction $B=10^{-2}$ tesla, a circular coil of radius 30 cm and resistance $\pi^{2}$ ohm is rotated about an axis which is perpendicular to the direction of $B$ and which forms a diameter of the coil. If the coil rotates at 200 rpm the amplitude of the alternating current induced in the coil is\

Professor PC Thomas Classes · Answer

(c) : $I_{0}=\frac{E_{0}}{R}=N \frac{B A \omega}{R}$ Given, $N=1, B=10^{-2} \mathrm{~T}, A=\pi(0.3)^{2} \mathrm{~m}^{2}, R=\pi^{2} \Omega$\ $f=(200 / 60)$ and $\omega=2 \pi(200 / 60)$\ Substituting these values and solving, we get $$ I_{0}=6 	imes 10^{-3} \mathrm{~A}=6 \mathrm{~mA}^{	op} $$