A coordination complex compound of cobalt has the molecular formula containing five ammonia molecule

Question

A coordination complex compound of cobalt has the molecular formula containing five ammonia molecules, one nitro group and two chlorine atoms for one cobalt atom. One mole of this compound produces three mole ions in an aqueous solution. On reacting this solution with excess of $\mathrm{AgNO}_{3}$ solution, we get two moles of AgCl precipitate. The ionic formula for this complex would be\

Professor PC Thomas Classes · Answer

(a) : As the complex gives two moles of AgCl ppt. with $\mathrm{AgNO}_{3}$ solution, so the complex must have two ionisable Cl atoms. Hence, the probable complex, which gives three mole ions may be $\left[\mathrm{Co}\left(\mathrm{NH}_{3}ight)_{5} \mathrm{NO}_{2}ight] \mathrm{Cl}_{2}$.\ $\left[\mathrm{Co}\left(\mathrm{NH}_{3}ight)_{5} \mathrm{NO}_{2}ight] \mathrm{Cl}_{2} ightarrow\left[\mathrm{Co}\left(\mathrm{NH}_{3}ight)_{5} \mathrm{NO}_{2}ight]^{2+}+2 \mathrm{Cl}^{-}$\ one mole $ightarrow 3$ mole ions