The vector sum of two forces is perpendicular to their vector differences. In that case, the forces\

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(b) : Given : $\left(\vec{F}_{1}+\vec{F}_{2}ight) \perp\left(\vec{F}_{1}-\vec{F}_{2}ight)$\ $	herefore \quad\left(\vec{F}_{1}+\vec{F}_{2}ight) \cdot\left(\vec{F}_{1}-\vec{F}_{2}ight)=0$ $$ F_{1}^{2}-F_{2}^{2}-\vec{F}_{1} \cdot \vec{F}_{2}+\vec{F}_{2} \cdot \vec{F}_{1}=0 \Rightarrow F_{1}^{2}=F_{2}^{2} $$ i.e. $F_{1}, F_{2}$ are equal to each other in magnitude.\