A body moves a distance of 10 m along a straight line under the action of a 5 N force. If the work d

Question

A body moves a distance of 10 m along a straight line under the action of a 5 N force. If the work done is 25 J , then angle between the force and direction of motion of the body is\

Professor PC Thomas Classes · Answer

(a) : Distance $(s)=10 \mathrm{~m}$; Force $(F)=5 \mathrm{~N}$ and work done ( $W$ ) $=25 \mathrm{~J}$\ Work done $(W)=$ Fs $\cos 	heta$\ $	herefore 25=5 	imes 10 \cos 	heta=50 \cos 	heta$\ or $\cos 	heta=25 / 50=0.5$ or $	heta=60^{\circ}$