A ball of mass 2 kg and another of mass 4 kg are dropped together from a 60 feet tall building. Afte

Question

A ball of mass 2 kg and another of mass 4 kg are dropped together from a 60 feet tall building. After a fall of 30 feet each towards earth, their respective kinetic energies will be in the ratio of\

Professor PC Thomas Classes · Answer

(c) : Ratio of their kinetic energy is given as $$ \begin{aligned} & \frac{\mathrm{KE}_{1}}{\mathrm{KE}_{2}}=\frac{(1 / 2) m_{1} v_{1}^{2}}{(1 / 2) m_{2} v_{2}^{2}} \ & v^{2}=2 g s \end{aligned} $$ (zero initial velocity)\ which is same for both\ $	herefore \frac{\mathrm{KE}_{1}}{\mathrm{KE}_{2}}=\frac{m_{1}}{m_{2}}=\frac{2}{4}=\frac{1}{2}$.\