If $|\vec{A} imes \vec{B}|=\sqrt{3} \vec{A} \cdot \vec{B}$ then the value of $|\vec{A}+\vec{B}|$ i

Question

If $|\vec{A} 	imes \vec{B}|=\sqrt{3} \vec{A} \cdot \vec{B}$ then the value of $|\vec{A}+\vec{B}|$ is\

Professor PC Thomas Classes · Answer

(a) : $|\vec{A} 	imes \vec{B}|=\sqrt{3} \vec{A} \cdot \vec{B}$\ $|\vec{A}||\vec{B}| \sin 	heta=\sqrt{3}|\vec{A}||\vec{B}| \cos 	heta$\ $	an 	heta=\sqrt{3} \Rightarrow 	heta=60^{\circ}$\ $|\vec{A}+\vec{B}|=\sqrt{|\vec{A}|^{2}+|\vec{B}|^{2}+2|\vec{A}||\vec{B}| \cos 	heta}$\ $=\left(A^{2}+B^{2}+A Bight)^{1 / 2}$\