The angular speed of a fly wheel moving with uniform angular acceleration changes from 1200 rpm to 3

Question

The angular speed of a fly wheel moving with uniform angular acceleration changes from 1200 rpm to 3120 rpm in 16 seconds. The angular acceleration in $\mathrm{rad} / \mathrm{s}^{2}$ is\

Professor PC Thomas Classes · Answer

(b) : Initial angular speed, 
$ \omega_{0}=\frac{2 \pi 	imes 1200}{60} \mathrm{rad} \mathrm{~s}^{-1}=40 \pi \mathrm{rad} \mathrm{~s}^{-1} $
 Final angular speed, 
$ \omega=\frac{2 \pi 	imes 3120}{60} \mathrm{rad} \mathrm{~s}^{-1}=104 \pi \mathrm{rad} \mathrm{~s}^{-1} $
 $	herefore$ Angular acceleration, 
$ \alpha=\frac{\omega-\omega_{0}}{t}=\frac{104 \pi-40 \pi}{16}=4 \pi \mathrm{rad} \mathrm{~s}^{-2} $