The diameter of a flywheel is increased by $1 \%$. What is the percentage increase in M.I. about cen

Question

The diameter of a flywheel is increased by $1 \%$. What is the percentage increase in M.I. about central axis\

Professor PC Thomas Classes · Answer

$\mathrm{I}=\frac{\mathrm{MR}^{2}}{2} \quad$ But $\mathrm{M}=\mathrm{V} ho=\pi \mathrm{R}^{2} \mathrm{~L} ho$ therefore $$\begin{align}
I &= \pi R^{2} L ho 	imes \frac{R^{2}}{2} \
&= \left(\frac{\pi L ho}{2}ight) R^{4}
\end{align}$$ When the radius increases by $1 \%$ the MI increases by $4 	imes 1 \%$\