The radius of gyration of solid cylinder of mass M and radius R about its own axis is\

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Professor PC Thomas Classes · Answer

The moment of inertia of a solid cylinder of mass $M$ and radius $R$ about its own axis is\ $\mathrm{I}=\frac{\mathrm{MR}^{2}}{2}$\ As $\mathrm{I}=\mathrm{MK}^{2}$\ Where $K$ is the radius of gyration From (i) and (ii), we get\ $\mathrm{K}^{2}=\frac{\mathrm{R}^{2}}{2}$ or $\mathrm{K}=\frac{\mathrm{R}}{\sqrt{2}}$\