Consider the change in oxidation state of bromine corresponding to different emf values as shown in

Question

Consider the change in oxidation state of bromine corresponding to different emf values as shown in the given diagram :\ Then the species undergoing disproportionation is\

Professor PC Thomas Classes · Answer

(d) : For a reaction to be spontaneous, $E_{	ext {cell }}^{\circ}$ should be positive as $\Delta G^{\circ}=-n F E_{	ext {cell }}^{\circ}$\ $\mathrm{HBrO} \longrightarrow \mathrm{Br}_{2} ; E^{\circ}=1.595 \mathrm{~V}$, SRP (cathode)\ $\mathrm{HBrO} \longrightarrow \mathrm{BrO}_{3}^{-} ; E^{\circ}=-1.5 \mathrm{~V}$, SOP (anode)\ $2 \mathrm{HBrO} \longrightarrow \mathrm{Br}_{2}+\mathrm{BrO}_{3}^{-}$\ $E_{	ext {cell }}^{\circ}=$ SRP (cathode) - SRP (anode)\ $=1.595-1.5=0.095 \mathrm{~V}$\ $E_{	ext {cell }}^{\circ}>0 \Rightarrow \Delta G^{\circ}<0$ (spontaneous)