Consider the table $\mathrm{E}^{0}$ (in volts) \ The strongest oxidising agent is\

Question

Professor PC Thomas Classes · Answer

The greater the $\mathrm{E}^{\ominus}$ value, the stronger the oxidising agent. $\mathrm{F}_{2} / \mathrm{F}^{-}$has the highest value. $\mathrm{F}^{-}$ can not act as an oxidising agent since it can not accept electrons further.\