3.19 g of chloroplatinate of a monoacidic organic base gave 1.04 g of platinum on ignition. Molecula

Question

3.19 g of chloroplatinate of a monoacidic organic base gave 1.04 g of platinum on ignition. Molecular mass of the base is\

Professor PC Thomas Classes · Answer

$$
2 \mathrm{~B}+\mathrm{H}_2 \mathrm{Pt} \mathrm{Cl}_6 ightarrow \mathrm{~B}_2 \mathrm{H}_2 \mathrm{Pt} \mathrm{Cl}_6 ightarrow \mathrm{Pt}
$$                                                      (2E)          (410)                    w1              w2 \
Molecular mass of salt $$ =2 \mathrm{E}+410=\frac{\mathrm{w}_{1} 	imes 195}{\mathrm{w}_{2}} $$ $$ \begin{aligned} \mathrm{E} & =\frac{1}{2}\left[\frac{\mathrm{w}_{1} 	imes 195}{\mathrm{w}_{2}}-410ight] \ & =\frac{1}{2}\left[\frac{3.19 	imes 195}{1.04}-410ight]=94 \end{aligned} $$ Molecular mass of base = equ.mass $	imes$ acidity $$ =\mathrm{E} 	imes 1=94 	imes 1=94 $$