On a new scale of temperature (which is linear) and called the $W$ scale, the freezing and boiling p

Question

On a new scale of temperature (which is linear) and called the $W$ scale, the freezing and boiling points of water are $39^{\circ} \mathrm{W}$ and $239^{\circ} \mathrm{W}$ respectively. What will be the temperature on the new scale, corresponding to a temperature of $39^{\circ} \mathrm{C}$ on the Celsius scale ?\

Professor PC Thomas Classes · Answer

(d) $	herefore \quad 39^{\circ} \mathrm{C}=39 	imes 2+39=(78+39)^{\circ} \mathrm{W}$ $$ =117^{\circ} \mathrm{W} $$