A bubble of 8 mole of helium is submerged at a certain depth is water. The temperature of water incr

Question

A bubble of 8 mole of helium is submerged at a certain depth is water. The temperature of water increases by $30^{\circ} \mathrm{C}$. How much heat is added approximately to helium during expansion?\

Professor PC Thomas Classes · Answer

Rise in temperature $\Delta T=30^{\circ} \mathrm{C}$\ $	herefore$ The quantity of heat added is $\Delta Q$\ $\Delta \mathrm{Q}=\mathrm{nC}_{\mathrm{p}} \Delta \mathrm{T}=8 	imes \frac{5}{2} \mathrm{R} 	imes 30=600 \mathrm{R}$\ $=4988 \mathrm{~J}=5000 \mathrm{~J}$\ R , the universal gas constant $=8.314 \mathrm{Jmol}^{-1} \mathrm{~K}^{-1}$.\