A 2 kg copper block is heated to $500^{\circ} \mathrm{C}$ and then it is placed on a large block of

Question

A 2 kg copper block is heated to $500^{\circ} \mathrm{C}$ and then it is placed on a large block of ice at $0^{\circ} \mathrm{C}$. If the specific heat capacity of copper is $400 \mathrm{Jkg}^{-1}{ }^{\circ} \mathrm{C}^{-1}$ and latent heat of fusion of water is $3.5 	imes 10^{5} \mathrm{Jkg}^{-1}$, the amount of ice that can melt is\

Professor PC Thomas Classes · Answer

Let xkg of ice can melt. Using law of calorimetry,\ Heat lost by copper = heat gain by ice\ $2 	imes 400 	imes(500-0)=\mathrm{x} 	imes 3.5 	imes 10^{5}$\ or, $\mathrm{x}=\frac{2 	imes 400 	imes 500}{3.5 	imes 10^{5}}=\frac{8}{7} \mathrm{~kg}$\