Consider the given data with frequency distribution
Match each entry in List-I to the correct entrie

Question

Consider the given data with frequency distribution
Match each entry in List-I to the correct entries in List-III.  The correct option is:

Professor PC Thomas Classes · Answer

(a) :  Mean $=\frac{15+16+33+20+20+16}{20}=6$\ Median = 5\ Mean deviation (about mean)\ $=\frac{15+4+15+8+4+8}{20}=\frac{54}{20}=2.7$\ Mean deviation (about median)\ $=\frac{10+6+18+10+0+4}{20}=\frac{48}{20}=2.4$\ Hence option (a)\