Statement-1 : The variance of first $n$ even natural numbers is $\frac{n^{2}-1}{4}$. Statement-2 : T

Question

Statement-1 : The variance of first $n$ even natural numbers is $\frac{n^{2}-1}{4}$. Statement-2 : The sum of first $n$ natural numbers is $\frac{n(n+1)}{2}$ and the sum of squares of first $n$ natural ${ }^{2}$ numbers is $\frac{n(n+1)(2 n+1)}{6}$.

Professor PC Thomas Classes · Answer

(c)