The standard entropy change for the reaction:\ $4 \mathrm{Fe}_{(\mathrm{s})}+3 \mathrm{O}_{2(\mathr

Question

The standard entropy change for the reaction:\ $4 \mathrm{Fe}_{(\mathrm{s})}+3 \mathrm{O}_{2(\mathrm{~g})} ightarrow 2 \mathrm{Fe}_{2} \mathrm{O}_{3(\mathrm{~s})}$ is $-550 \mathrm{~J} \mathrm{~K}^{-1}$ at 298 K .\ [Given : The standard enthalpy change for the reaction is $-165 \mathrm{~kJ} \mathrm{~mol}^{-1}$ ].\ The temperature in K at which the reaction attains equilibrium is $\qquad$ (Nearest integer)\

Professor PC Thomas Classes · Answer

(300): $\Delta G=\Delta H-T \Delta S$ At equilibrium, $\Delta G=0 ; \Delta H=T \Delta S$\ $T=\frac{\Delta H}{\Delta S}=\frac{-165 	imes 10^{3} \mathrm{~J} / \mathrm{mol}}{-550 \mathrm{JK}^{-1}}=300 \mathrm{~K}$\