An AC source of voltage $E=20 \sin 100 \pi t$ is connected across a resistance $20 \Omega$. The rms

Question

An AC source of voltage $E=20 \sin 100 \pi t$ is connected across a resistance $20 \Omega$. The rms value of current in the circuit is\

Professor PC Thomas Classes · Answer

$\mathrm{E}=20 \sin 100 \mathrm{t}$ Here, $\mathrm{E}_{0}=20 \mathrm{~V}$ andR $=20 \Omega$\ $	herefore$ rms value of current in circuit $\mathrm{I}_{	ext {rms }}=\frac{\mathrm{I}_{0}}{\sqrt{2}}$\ $=\frac{\mathrm{E}_{0}}{\mathrm{R}}=\frac{20 / 20}{\sqrt{2}}=\frac{1}{\sqrt{2}}$\