If $\mathrm{E}_{0}$ is the peak emf, $\mathrm{I}_{0}$ is the peak current and $\phi$ is the phase di

Question

If $\mathrm{E}_{0}$ is the peak emf, $\mathrm{I}_{0}$ is the peak current and $\phi$ is the phase difference between them, then the average power dissipation in the circuit is\

Professor PC Thomas Classes · Answer

Average power dissipation $=\frac{1}{2} \mathrm{E}_{0} \mathrm{I}_{0} \cos \phi$\