A copper rod of length $L$ rotates with an angular velocity in a uniform magnetic field $B$. The emf

Question

A copper rod of length $L$ rotates with an angular velocity in a uniform magnetic field $B$. The emf developed between the two ends of the rod is\

Professor PC Thomas Classes · Answer

$\varepsilon=\mathrm{B} \pi \mathrm{L}^{2} \mathrm{n}, \mathrm{n}=$ frequency\ $=\frac{1}{2} B L^{2}(2 \pi n)$\