The flux (in weber) in closed circuit of a resistance 10 ohms varies with time $t$ (in seconds) acco

Question

The flux (in weber) in closed circuit of a resistance 10 ohms varies with time $t$ (in seconds) according to equation $\phi=6 t^{2}-5 t+1$. What is magnitude of induced current at $t=02.5$ seconds\

Professor PC Thomas Classes · Answer

$\phi=6 t^{2}-5 t+1$\ $\frac{d \phi}{d t}=12 t-5$\ $\left(\frac{\mathrm{d} \phi}{\mathrm{dt}}ight)_{\mathrm{att}=0.25}=12 	imes 0.25-5=-2$\ $\varepsilon=\frac{-\mathrm{d} \phi}{\mathrm{dt}}=2 \mathrm{~V}$\ $\mathrm{I}=\frac{\varepsilon}{\mathrm{R}}=\frac{2}{10}=0.2 \mathrm{~A}$\