The diagram given below represents an area $A=0.5 \mathrm{~m}^{2}$ situated in a uniform magnetic fi

Question

The diagram given below represents an area $A=0.5 \mathrm{~m}^{2}$ situated in a uniform magnetic field $B=2.0$ weber $/ \mathrm{m}^{2}$ and making an angle of $60^{\circ}$ with respect to the magnetic field. The value of the magnetic flux through the area A would be equal to\

Professor PC Thomas Classes · Answer

$\phi=\overline{\mathrm{B}} \cdot \overline{\mathrm{A}}$\ $=\mathrm{BA} \cos 	heta$\ $=2 	imes 0.5 	imes \cos 60$\ $=\mathrm{Wb}$.\