A wire of length 50 cm moves with a velocity 300 mmin , perpendicular to a magnetic field the emf in

Question

A wire of length 50 cm moves with a velocity 300 mmin , perpendicular to a magnetic field the emf induced in the wire is 2 V , the magnetic of the field in tesla is\

Professor PC Thomas Classes · Answer

When a wire of length $l$ moves with veructu v, perperiumurar to a magnetic field B , the induced emf is produced. The magnitude of induced emf is given by $|\varepsilon|=\mathrm{B} \ell \mathrm{v}$\ Given $\mathrm{I}=50 \mathrm{~cm}=0.5 \mathrm{~m}, \mathrm{v}=300 \mathrm{~m} / \mathrm{min}=5 \mathrm{~m} / \mathrm{s}$\ $|\varepsilon|=2 \mathrm{~V}$.\ or, $\mathrm{B}=\frac{|\varepsilon|}{\ell \mathrm{v}}=\frac{2}{0.5 	imes 5}=0.8$ tesla\