When AgBr is treated with sodium thiosulphate solution, the complex compound formed is\

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Professor PC Thomas Classes · Answer

AgBr reacts with sodium thiosulphate solution to form water soluble complex $\mathrm{Na}_{3}\left[\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}ight)_{2}ight]$.\ $\mathrm{AgBr}+2 \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3} ightarrow \mathrm{Na}_{3}\left[\mathrm{Ag}\left(\mathrm{S}_{2} \mathrm{O}_{3}ight)_{2}ight]+\mathrm{NaBr}$.\ Co.ordination number of $\mathrm{Ag}^{+}$is two and $\mathrm{S}_{2} \mathrm{O}_{3}^{2-}$ ie thiosulphate anion is a monodentate ligand.