The stability of the complexes $\mathrm{Mn}_{2}(\mathrm{CO})_{10}$ and $\mathrm{Co}_{2}(\mathrm{CO})

Question

The stability of the complexes $\mathrm{Mn}_{2}(\mathrm{CO})_{10}$ and $\mathrm{Co}_{2}(\mathrm{CO})_{8}$ can be explained respectively on the basis of\

Professor PC Thomas Classes · Answer

$\mathrm{Mn}_{2}(\mathrm{CO})_{10}$ is $(\mathrm{CO})_{5} \mathrm{Mn}-\mathrm{Mn}(\mathrm{CO})_{5}$ No. of electrons in the valency shell $=7$\ No.of electrons from the five ligands $$ =2 	imes 5=10 $$ No.of electron from $\mathrm{Mn}-\mathrm{Mn}$ covalent bond $=1$\ $	herefore$ Total no. of $\mathrm{e}^{-}$in the valency shell of\ Mn=18-stable.\ $\mathrm{Co}_{2}(\mathrm{CO})_{8}$ is\ No. of electrons in the valency shell of $\mathrm{Co}=9$\ No. of electrons from 3 ligands $=2 	imes 3=6$\ No. of electrons from 2 bridge bonds $=1 	imes 2=2$\ No. of electrons from $\mathrm{Co}-\mathrm{Co}$ covalent bond $=1$\ Total no $\mathrm{e}^{-}$in the valency shell of $$ 	ext { Co }=18 	ext { - stable } . $$ The stability of these complexes can also be explained by EAN. Both are having EAN 36stable.\