An ideal gas heat engine operated in a Carnot cycle between $227^{\circ} \mathrm{C}$ and $127^{\circ

Question

An ideal gas heat engine operated in a Carnot cycle between $227^{\circ} \mathrm{C}$ and $127^{\circ} \mathrm{C}$. It absorbs $6 	imes 10^{4} \mathrm{cal}$ at the higher temperature. The amount of heat converted into work is equal to\

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For a Carnot's engine $$ \begin{aligned} & \frac{Q_{1}}{Q_{2}}=\frac{T_{1}}{T_{2}} \quad T_{1}=	ext { temp of source } \ & \frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{T_{2}-T_{1}}{T_{1}} \quad T_{2}=	ext { temp of sink } \ & \begin{aligned} & Q_{1}-Q_{2}=	ext { work done } W Q_{1}=	ext { heat absorbed } \ & Q_{2}=	ext { heater ejected } \end{aligned} \ & \begin{aligned} \frac{W}{Q_{1}}=\frac{T_{1}-T_{2}}{T_{1}} & T_{1}=227^{\circ} \mathrm{C} \ & =500 \mathrm{~K} \ T_{2} & =127^{\circ} \mathrm{C} \ & =400 \mathrm{~K} \end{aligned} \end{aligned} $$ Substitute & $\quad \mathrm{Q}_{1}=6 	imes 10^{4} \mathrm{cal}$ calculate W in calories\