A Carnot's engine whose source is at 400 K takes 200 cals of heat and rejects 150 cals to sink. The

Question

A Carnot's engine whose source is at 400 K takes 200 cals of heat and rejects 150 cals to sink. The temp. of sink is\

Professor PC Thomas Classes · Answer

$\frac{\mathrm{T}_{1}-\mathrm{T}_{2}}{\mathrm{~T}_{1}}=\frac{\mathrm{Q}_{1}-\mathrm{Q}_{2}}{\mathrm{Q}_{1}}$\ $\mathrm{T}_{1}=400 \mathrm{~K}$\ $\mathrm{T}_{2}=$ ?\ $\mathrm{Q}_{1}=200 \mathrm{cal}$\ $\mathrm{Q}_{2}=150 \mathrm{cal}$\ Calculate $\mathrm{T}_{2}$\