For a heat engine the temperature of the source is $127^{\circ} \mathrm{C}$. To have $60 \%$ efficie

Question

For a heat engine the temperature of the source is $127^{\circ} \mathrm{C}$. To have $60 \%$ efficiency, the temperature of the sink is\

Professor PC Thomas Classes · Answer

Efficiency $\eta=1-\frac{T_{2}}{T_{1}}$\ i.e. $\frac{60}{100}=1-\frac{\mathrm{T}_{2}}{127+273}$\ $	herefore \mathrm{T}_{2}=400\left(1-\frac{60}{100}ight)=160 \mathrm{~K}=-113^{\circ} \mathrm{C}$\