The product of $n$ positive numbers is unity. Then their sum is\

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(d) : Option (d) is correct because A.M. $\geq$ G.M. and thus\ $\frac{1}{n}\left[r_{1}+r_{2}+r_{3}+\ldots . .+r_{n}ight] \geq\left(r_{1} r_{2} \ldots . . r_{n}ight)^{\frac{1}{n}}=1$\ where $r_{1}, r_{2}$,\ $r_{n}$ are + ve numbers